3x^2+2x-7=3x-6

Solution for 3x^2+2x-7=3x-6 equation:

3x^2+2x-7=3x-6

We move all terms to the left:

3x^2+2x-7-(3x-6)=0

We get rid of parentheses

3x^2+2x-3x+6-7=0

We add all the numbers together, and all the variables

3x^2-1x-1=0

a = 3; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·3·(-1)
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{13}}{2*3}=\frac{1-\sqrt{13}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{13}}{2*3}=\frac{1+\sqrt{13}}{6}
$